0 Members and 1 Guest are viewing this topic.
A rheostat is nothing but a resistor.
That big rheostat drops voltage proportional to how much current is being drawn.So with a loco motor that draw 0.5 amp, at half throttle, let's say it drops about 6v. ( Those are pretty typical numbers, by the way. In the old days, it wasn't uncommon for loco motors to draw 1/4 to 1/2 amp. )So if 12 volts is the maximum output, and the rheostat drops 6 at half throttle, in this case then there will be6 volts remaining. That means 6 volts across the motor and it will run at a moderate speed.To really understand why it won't work:This is really all about Ohm's Law, which I quietly suggest everyone become acquainted with because it is so simple and yetgoes a long way to understand throttles, LEDs, resistors, and a whole boat load of other issues that come up on model railroads over and over.V = I x R Voltage = current x resistanceIf 0.5 amp through that rheostat drops 6 volts, that means:6 = 0.5 x RRearranging:R = 6 / 0.5 = 12 ohmsOkay, so at half throttle, that rheostat is a 12 ohm resistor.Now, what happened to your newer engine?Your new engine draws, maybe, 0.1 amp. Engines don't use nearly as much current as they used to.V = 0.1 x 12 = 1.2 voltsSo now at half throttle, that rheostat drops only 1.2 volts. 12 volts comes into it, it drops only 1.2, so the outputis 12 - 1.2 = 10.8 volts.
Yes I agree, a rheostat is a wire wound variable resistor. OK, why are you continuing to use 12 ohms in your second calculation? if the motor only draws 0.1 amp and half way down the rheostat is 6 volts, then now according to ohms law, that rheostat would be a 60 ohm resistor? R = 6 / 0.1 = 60 ohm.
If you could find one of the old power packs that used a variable transformer before the rectifier, instead of a rheostat after it, you'd be set. In the 50s those were considered the high-end models, but then transistors replaced them.
To answer all this:The resistance at any point on that rheostat is constant. We figured out in the first motor example that it is 12 ohms athalf throttle.In answer to this:OK, why are you continuing to use 12 ohms in your second calculation? if the motor only draws 0.1 amp and half way down the rheostat is 6 volts, then now according to ohms law, that rheostat would be a 60 ohm resistor?R = 6 / 0.1 = 60 ohm.No, halfway down the throttle is not 6 volts. It was only 6 volts for the first motor. That's the whole point.The resistance at half throttle is constant. The voltage is not.In other words, the "R" in your equation is not a variable. It is 12.The current is also not variable. It is 0.1 amp. The thing that varies is the voltagethat drops across the rheostat.12 = V / 0.1 V = 1.2And in fact, any motor with a different current draw will cause a different amount of voltage to be dropped bythe rheostat.